线性规划如何求出区间估计

Question

现在我想对一组数据进行线性规划，并给出预测值的置信区间
数据如下
data2 = {{391.95, 488.51}, {516.98, 798.30}, {355.63, 
    235.08}, {238.55, 299.45}, {537.78, 559.09}, {733.78, 
    1133.25}, {198.83, 348.74}, {252.62, 417.78}, {206.20, 
    344.52}, {231.18, 323.08}, {449.76, 620.75}, {288.57, 
    423.30}, {185.74, 202.61}, {1164.39, 1531.53}, {444.58, 
    553.48}, {412.87, 685.97}, {272.28, 324.24}, {781.80, 
    983.24}, {1209.22, 1762.02}, {825.51, 960.31}, {223.75, 
    284.61}, {354.84, 407.76}, {515.52, 982.66}, {220.46, 
    557.00}, {337.67, 440.92}, {197.12, 268.06}, {133.24, 
    262.05}, {374.01, 432.50}, {273.84, 338.36}, {570.36, 
    704.32}, {391.29, 585.68}, {201.86, 267.78}, {321.63, 
    408.34}, {838.90, 1165.57}};

lm = LinearModelFit[data2, x, x]

lm[{"MeanPredictionConfidenceIntervalTable", "SinglePredictionConfidenceIntervalTable"}]

使用上面的可以求出给出的点的置信区间

要是我想求出 x = 2000时的区间应该怎么做

只知道求2000时的具体的值 lm[2000]即可

Answer 1

你是想要这种？

lm[{"MeanPredictionBands", "SinglePredictionBands"}] /. x -> 2000

 

Comments

是的，就是这个。